That's the only pair.
No, because every other even number besides 2 is composite and odd numbers are never adjacent.
No, it has four pairs. If the sides are labelled a, b, c and d, the four adjacent pairs are ab, bc, cd and da. The fourth can be derived from the other three. However, two pairs is not enough for a rhombus. A kite, for example, has two pairs of congruent adjacent sides: ab and cd.
No, it has four pairs. If the sides are labelled a, b, c and d, the four adjacent pairs are ab, bc, cd and da. The fourth can be derived from the other three. However, two pairs is not enough for a rhombus. A kite, for example, has two pairs of congruent adjacent sides: ab and cd.
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There are not three odd primes with the sum of 14. The sum of three odd primes will be an odd number.
Yes, all primes over three are either of the form 6n - 1 or 6n + 1. So the only way for them to be prime pairs is for one to be of the same n, one -1 and the other +1; so the number between them is always of the form 6n, and thus always divisible by six.
Sure. All composite numbers can be written as a product of primes. It shouldn't be tough to find a composite number that's the sum of three other composite numbers. Let's try 30. 2 x 3 x 5 = 30 Product of primes, check. 6 (2 x 3) + 10 (2 x 5) + 14 (2 x 7) = 30 Sum of three products of primes, check.
This question cannot be answered because three odd primes always have an odd number for their sum.
3
No.
8 has three primes (2x2x2) in its factorization, and 30 is the smallest number having three different primes (2x3x5) in its factorization.
30, which is the smallest positive integer divisible by the first three primes: 2, 3 and 5.