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Q: What are the coordinates of the center of the circle described by the equation x2 y 52 16?
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How do you write the equation of a circle?

The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius


What are the center and radius of the circle described by the equation (x - 6)2 (y - 8)2 9?

Center of circle: (6, 8) Radius of circle: 3


How do you find the general form equation of a circle?

There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.


How do you solve the circle?

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.


How do you find the radius and the coordinates of the center for each circle?

The answer depends on what information is available and in what form.The simplest solution is to write the equation of the circle in the following form:(x - a)^2 + (y - b)^2 = r^2Hiving done that, the coordinates of the centre are (a, b), and the circle's radius is r.


What is the equation of a circle with radius 10 and center -3 and 6?

Equation of a circle is given by: (x-a)2 + (y-b)2 = r2 Here a & b are the coordinates of the center. So, a = -3 & b = 6. And r = 10. Thus, the equation formed is (x+3)2+(y-6)2 = 102


What are the center and radius of the circle described by the equation (x-7)2 (y 6)2100?

To determine the center and radius of a circle described by an equation in the form "(x-h)^2 + (y-k)^2 = r^2", we need to rewrite the given equation in that form. The equation (x-7)^2 + (y-6)^2 = 2100 is already in that form. Therefore, the center of the circle is at the point (7, 6) and the radius is the square root of 2100.


What are the center and radius of the circle described by the equation (x 4)2 (y - 3)2 4?

I think it is center: (-4, 3) ; radius: 2 Apex:)


How do you calculate the coordinates of center of a rotation?

In the algebraic equation for a circle. (x - g)^2 + (y - h)^2 = r^2 'g' & 'h' are the centre of rotation.


How do you write an equation for a circle with a center?

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2


How is the equation of an ellipses like the equation of the circle?

An ellipse is described as [ (x/A)2 + (y/B)2 = C2 ] If [ A=B ] then the ellipse is a circle.


What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?

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