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How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
What is the center point in the following equation of the circle?
To identify the center point of a circle from its equation, you typically look for the standard form of the circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2). In this format, ((h, k)) represents the center of the circle, where (h) and (k) are constants. If you provide the specific equation of the circle, I can help you determine the center point.
How do you Writing the Equation of a Circle in Standard Form?
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
What are the coordinates of the center of the circle described by the equation x2 y 52 16?
The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
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What is the center point in the following equation of the circle?
To identify the center point of a circle from its equation, you typically look for the standard form of the circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2). In this format, ((h, k)) represents the center of the circle, where (h) and (k) are constants. If you provide the specific equation of the circle, I can help you determine the center point.
How do you Writing the Equation of a Circle in Standard Form?
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
What are the coordinates of the center of the circle described by the equation x2 y 52 16?
The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
How To find the standard equation for a circle centered at the origin we use the distance formula since the radius measures?
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
Which is the standard equation for a circle centered at origin with raduis r?
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
When you make the circle smaller which number in the standard equation for a circle center the orgin decreases?
In the standard equation for a circle centered at the origin, ( x^2 + y^2 = r^2 ), the radius ( r ) determines the size of the circle. When you make the circle smaller, you decrease the radius ( r ). Consequently, the value of ( r^2 ) also decreases, resulting in a smaller circle. Thus, the number that decreases in the equation is ( r^2 ).
What is the center of the circle given by the equation ((x plus 5)2 (y-8)21?
The equation you provided appears to be incorrectly formatted. However, if you meant to write the standard form of a circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2), then the center of the circle is given by the point ((h, k)). For the specific equation you intended, please clarify the format, and I can help identify the center accordingly.
What is the center of the circle given by the equation (x - 3)2 (y - 9)2 16?
Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.
How do you write an equation for a circle with a center?
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
