The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
depends on the equation.
(x - h)2 + (y - v)2 = r2
There is no such thing as a standard equation. Furthermore, there are standard forms - all different - for the equation of a line, a circle, a plane, a parabola, an ellipse and so on. the question needs to be more specific.
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
9
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
32+62=45 so the standard form is x2+y2=45
(x - h)2 + (y - k)2 = r2 where h is the x coordinate of the center of the circle. where k is the y coordinate of the center of the circle. where x is the x coordinate of point (x,y) on the edge of the circle. where y is the y coordinate of point (x,y) on the edge of the circle. Additional assistance here: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php
depends on the equation.
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
You should increase the radius in the standard equation of a circle centered at the origin. The general form is ( x^2 + y^2 = r^2 ), where ( r ) is the radius. By increasing ( r ), you extend the distance from the center to any point on the circle, making it larger.
(x-2)^2 +(y-3)^2 = 16
(x - h)2 + (y - v)2 = r2
The equation of the circle is: x^2 + y^2 = 81