Let the length be (x+2) and the width be x:
length*width = 2(length+width)
(x+2)*x = 2(x+2+x)
x2+2x = 4x+4
x2+2x-4x-4 = 0
x2-2x-4 = 0
Solving the above quadratic equation gives a positive value of 3.236067977 for x.
Therefore: length = 5.236067977 cm and width = 3.236067977 cm
Check: length*width = 16.94427191 cm2 and 2(length+width) = 16.94427191 cm
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
It is: 12 units in length
Length = 3.5 inches and Width = 2.5 inches Check: 2(3.5+2.5) = 12 inches
it depend on the dimensions of the cube and the rectangle
a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
The dimensions are: length 10.5 cm and width 3.5 cm Check: 2*(10.5+3.5) = 28 cm
L + W >= 24, L = W + 4, Possible dimensions 14 and 10 giving an area of 140 sq cm.
perimeter = 2(length X width) = 2(l x w) = 2(w+7+w) - 2(2w+7)=142 2w+7 = 71; 2w=64; w = 32 and l = w+7 = 39 Check: perimeter = 2(32+37) = 142
21cm3
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
It is: 12 units in length
Length = 3.5 inches and Width = 2.5 inches Check: 2(3.5+2.5) = 12 inches
The smallest is just over 40 units. At 40 units it is no longer a rectangle but a square. There is no largest perimeter.
Let x represent width. Using the formula 3x(x)=44cm, the equation is complete when x = 3.82. This means that the rectangle is 3.82 cm wide, and 11.46 cm long.
17 and 22
i don't know what length of rectangle is 7 cm longer than the width the perimeter of the rectangle is 46 cm .what is the length of the of the rectangle ?