2 * 2 * 2 * 2 * x * x * x = 16x^3
[(-16x)12]1/3 = (-16x)4 = 65536x4
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
16 and x
x3 + 4x2 + 16x + 64 =x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.
(4x - 3)(16x^2 + 12x + 9)
x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).
2 times 2 times 2 times 2 times x = 16x
4x(4x^2 + 3x + 1)
x3-16xx(x2-16)x(x+4)(x-4)...forgot to finish it, sorry.
In the absence of signs I have assumed the term in 16x and 60 are negative: ie x2 - 16x = -60 or x2 - 16x + 60 = 0 Factors of 60 which total -16 are -6 and -10, so (x - 6)(x - 10)
That factors to (x - 14)(x - 2)
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.