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What is the cubed root of -16x to the 12th power?
[(-16x)12]1/3 = (-16x)4 = 65536x4
How do you factor 64 x cubed minus y cubed?
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
How do you factor x cubed plus 4x squared plus 16x plus 64?
x3 + 4x2 + 16x + 64 =x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.
How do you factor the expression 64x cubed minus 27?
(4x - 3)(16x^2 + 12x + 9)
How do you factor X cubed plus 4 x squared minus 16x minus 64?
x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).
What are the factors for 16X?
16 and x
How do you factor a polynomial of 4x plus 12x squared plus 16x cubed?
Re=Write as 16x^(3) + 12x^(2) + 4x Take out the common factor of '4' Hence 4(4x^(3) + 3x^)2) + x) Take out the common factor of 'x' Hence 4x( 4x^(2) + 3x + 1) The answer!!!!!
What are the prime factors of 16x?
2 times 2 times 2 times 2 times x = 16x
How do you factorise x cubed -16x?
x3-16xx(x2-16)x(x+4)(x-4)...forgot to finish it, sorry.
How do you factor x2 16x equals 60?
In the absence of signs I have assumed the term in 16x and 60 are negative: ie x2 - 16x = -60 or x2 - 16x + 60 = 0 Factors of 60 which total -16 are -6 and -10, so (x - 6)(x - 10)
What is 16x 3/5?
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
X2 - 16x plus 28 binomials trinomial?
That factors to (x - 14)(x - 2)
