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I am assuming that 2n is an algebraic expression, and n is limited to positive integer values.
The first 4 multiples of 2n are 0 (2n*0), 2n (2n*1), 4n (2n*2), and 6n (2n*3). If you are looking for non-0 multiples, you would also include 8n (2n*4).
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How do you solve 17 plus 2n equals 21 plus 2n?
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
What are the first four terms of a sequence for 2n plus 4 divided by 2?
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
What is 2n plus 4?
It's an algbraic expession in the form of: 2n+4
What are three consecutive even integers whose sum is 108?
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
What is the first 3 terms if the nth term is 2n?
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.
Find the first 3 terms and 50th and 100th term for 2n plus 4?
2n+4: 6,8,10......104........204
How to write the phase for 2n plus 4?
2n plus 4 = 2n + 4
Slove multi-step equations 4n-2n 4?
If you mean: 4n-2n = 4 then 2n = 4 and n = 2
How do you solve 17 plus 2n equals 21 plus 2n?
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
What is n in 2n-9 equals -4?
2n-9=-4
What are the first four terms of a sequence for 2n plus 4 divided by 2?
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
What is 2n plus 4?
It's an algbraic expession in the form of: 2n+4
What are three consecutive even integers whose sum is 108?
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
What is the algebric expression for 2n 4?
If you mean 2n+4, or 2n-4, that already is an algebraic expression. The idea might be to put it into words. 2n+4 is twice n, increased by 4. Notice you need a comma because if you write twice n increased by 4 this is 2(n+4)
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
Which is the complete factorization of 2n-6n-36?
First we must collect and simplify 'like terms' 2n-6n-36. 2n-6n = -4n Therefore, -4n-36 Take out the greatest common factor. -4 (n+9) Ans = -4 (n+9)
