0
The first three terms for the expression 2n-6 are obtained by substituting n with consecutive integers. When n=1, the expression evaluates to -4; when n=2, the expression evaluates to -2; and when n=3, the expression evaluates to 0. Therefore, the first three terms are -4, -2, and 0.
They are: -4, -2 and 0
-4,-2,0
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What are the first 3 terms for 2n-1?
To find the first three terms, plug 1, 2, and 3 in for n:Term 1: 2(1) - 1 = 1Term 2: 2(2) - 1 = 3Term 3: 2(3) - 1 = 5
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Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
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To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
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Well, honey, the first three terms for 3n + 7 are 10, 13, and 16. Just plug in n = 1, 2, and 3, and you'll see those numbers pop out like daisies in spring. Math can be a piece of cake once you get the hang of it!
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it is 8.
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3
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Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
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5
