0
The first three terms for the expression 2n-6 are obtained by substituting n with consecutive integers. When n=1, the expression evaluates to -4; when n=2, the expression evaluates to -2; and when n=3, the expression evaluates to 0. Therefore, the first three terms are -4, -2, and 0.
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RossOh, what a happy little question we have here! The first three terms for 2n-6 would be 2n-6, 2n, and 2n+6. Just remember, there are no mistakes in math, only happy little accidents.
They are: -4, -2 and 0
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What are the first 3 terms for 2n-1?
The first three terms for the expression 2n-1 can be found by substituting n with the first three consecutive integers. When n=1, the expression becomes 2(1)-1 = 1. When n=2, the expression becomes 2(2)-1 = 3. When n=3, the expression becomes 2(3)-1 = 5. Therefore, the first three terms are 1, 3, and 5.
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