They are: -4, -2 and 0
-4,-2,0
The first 3 are -4, -2 and 0! Good luck and have an awesome day.
To find the first three terms, plug 1, 2, and 3 in for n:Term 1: 2(1) - 1 = 1Term 2: 2(2) - 1 = 3Term 3: 2(3) - 1 = 5
29
You use the FOIL method. First terms Outer terms Inner terms Last terms.
We need the common difference to accurately get the first term and then use it to find the sum of the first 20 terms.
no it is a binomial. terms in an algebriac expression are separated by addition or subtraction ( + or -) symbols and must not be like terms. then just count the terms. one term = monomial, 2 terms = binomial, 3 terms = trinomial. More than 3 terms are usually just referred to as polynomials.
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
3 7 11
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
it is 8.
4, 8, 12
To find the first three terms, plug 1, 2, and 3 in for n:Term 1: 3(1) + 7 = 10Term 2: 3(2) + 7 = 13Term 3: 3(3) + 7 = 16
3
n = 1 ---> 3 * 1 + 3 = 6 n = 2 ---> 3 * 2 + 3 = 9 first 2 have difference of 3, so you can keep adding 3 to find more terms. 6, 9, 12, 15
The first four terms are 3 9 27 81 and 729 is the 6th term.
To find the first three terms, plug 1, 2, and 3 in for n:Term 1: 2(1) - 1 = 1Term 2: 2(2) - 1 = 3Term 3: 2(3) - 1 = 5
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
5