x+7 is greater than or equal to 2
One possible inequality that has x = 0.8 as a solution is x ≤ 0.8. This means that any value of x that is less than or equal to 0.8 will satisfy the inequality.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
5x-3 < 3x+1 5x-3x < 1+3 2x < 4 Divide both sides of the inequality by 2 to find the value of x: x < 2 So x is an integer whose value is less than 2 such as 1, 0, -1, -2, -3, .........
Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9
4 & |-4|
x - 3 is not an inequality.
If you mean (x-3)(x+5) = 0 then x = 3 or x = -5
that would be limited to 3 and -3 for values of x
x+7 is greater than or equal to 2
x^2<25
No, it can be an inequality, such as x+5>2. An inequality usually has (infinitely) many solutions.
sec x = 2 cos x = 1/2 x = PI/3 and x=5PI/3 The period of cosine is 2PI The general solutions are: x= PI/3 + 2nPI, where n is any integer x = 5PI/3+2nPI, where n is any integer
If limited to integer solutions, the answers are: 1*117, 3*39 and 9*13
One possible inequality that has x = 0.8 as a solution is x ≤ 0.8. This means that any value of x that is less than or equal to 0.8 will satisfy the inequality.
In solving an inequality you generally use the same methods as for solving an equation. The main difference is that when you multiply or divide each side by a negative, you have to switch the direction of the inequality sign. The solution to an equation is often a single value, but the solution to an inequality is usually an infinite set of numbers, such as x>3.
There is no equation (or inequality) in the question and so there cannot be any solutions.