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What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
How many sides does a regular polygon have if it has an interior angel of 171?
Interior angle = 180n - 360 = 171n so 9n = 360 and your polygon has 40 sides. This works because the interior angles of any n-sided polygon total 180n - 360 degrees, usually expressed as "(2n - 4) right angles"
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
What is the measure of each interior angle of a regular nonogon?
Method 1: Exterior angle of n-sided regular polygon is 360/n degrees, in this case 40 so interior angle is 180 - 40 ie 140 degrees; Method 2: Interior angles of regular n-sided polygon total 180n - 360 degrees, in this case 1260 degrees so each angle is 1260/9 ie 140 degrees.
What is the exterior and interior angles of a regular polygon with 9 sides?
Exterior angle = 360*9 = 40 degrees. So interior angle = 180 - 40 = 140 deg
What is the interior of a 40 side polygon?
The interior angles of a 40 sided polygon add up to 6840 degrees
What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
What is the sum of the interior angle measures of a 40- sided convex polygon?
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.
What is the exterior angle of a 9 sided polygon?
If its a regular 9 sided polygon then the exterior angles are 40 degrees.
What is the measure of one angle regular polygon with 9 sides?
Method 1: Interior angles of regular n-sided polygon are ((2n - 4) x 90)/n degrees When n = 9 this works out at 140 degrees. Method 2: Exterior angles of regular n-sided polygon are 360/n degrees in this case 40 degrees, making interior angles 180 - 40 ie 140 degrees.
How many sides does a regular polygon have if it has an interior angel of 171?
Interior angle = 180n - 360 = 171n so 9n = 360 and your polygon has 40 sides. This works because the interior angles of any n-sided polygon total 180n - 360 degrees, usually expressed as "(2n - 4) right angles"
What are the sum of the interior angles of a polygon with 40 sides?
The interior angles add up to 6840 degrees
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
What is the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 6840 degrees
What is the number of angles if the sum of the interiors angles are 40?
No polygon can have a sum of interior angles less than 180 degrees.
What is a 40 sided polygon?
The name of a 40 sided polygon is Tetracontagon.
Can a regular polygon's interior angles measure 40 degrees?
No. To elaborate, the smallest regular polygon, an equilateral triangle, has 60 degree interior angles. The next larger one, a square, has 90 degree interior angles. In fact, for any regular polygon, the interior angles measure 180*(n-2)/n degrees, where n is the number of sides. No polygon has less than 3 sides. Thus, no regular polygon can have interior angles less than 60 degrees.
