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What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
How many sides does a regular polygon have if it has an interior angel of 171?
Interior angle = 180n - 360 = 171n so 9n = 360 and your polygon has 40 sides. This works because the interior angles of any n-sided polygon total 180n - 360 degrees, usually expressed as "(2n - 4) right angles"
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
What is the measure of each interior angle of a regular nonogon?
Method 1: Exterior angle of n-sided regular polygon is 360/n degrees, in this case 40 so interior angle is 180 - 40 ie 140 degrees; Method 2: Interior angles of regular n-sided polygon total 180n - 360 degrees, in this case 1260 degrees so each angle is 1260/9 ie 140 degrees.
What is the exterior and interior angles of a regular polygon with 9 sides?
Exterior angle = 360*9 = 40 degrees. So interior angle = 180 - 40 = 140 deg
