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What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
How many sides does a regular polygon have if it has an interior angel of 171?
Interior angle = 180n - 360 = 171n so 9n = 360 and your polygon has 40 sides. This works because the interior angles of any n-sided polygon total 180n - 360 degrees, usually expressed as "(2n - 4) right angles"
What is the size of each interior angle in a regular 40-sided polygon?
In a regular 40-sided polygon (also known as a tetracontagon), each interior angle can be calculated using the formula ((n-2) \times 180^\circ / n), where (n) is the number of sides. For a 40-sided polygon, this yields ((40-2) \times 180^\circ / 40 = 38 \times 180^\circ / 40 = 171^\circ). Therefore, each interior angle in a regular 40-sided polygon measures 171 degrees.
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
What is the measure of each interior angle of a regular nonogon?
Method 1: Exterior angle of n-sided regular polygon is 360/n degrees, in this case 40 so interior angle is 180 - 40 ie 140 degrees; Method 2: Interior angles of regular n-sided polygon total 180n - 360 degrees, in this case 1260 degrees so each angle is 1260/9 ie 140 degrees.
What is the interior of a 40 side polygon?
The interior angles of a 40 sided polygon add up to 6840 degrees
What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
What is the sum of the interior angle measures of a 40- sided convex polygon?
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.
What is the exterior angle of a 9 sided polygon?
If its a regular 9 sided polygon then the exterior angles are 40 degrees.
What are the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of a polygon can be calculated using the formula: [ \text{Sum of interior angles} = (n - 2) \times 180^\circ ] where (n) is the number of sides of the polygon. For a polygon with 40 sides ((n = 40)): [ \text{Sum of interior angles} = (40 - 2) \times 180^\circ = 38 \times 180^\circ = 6840^\circ ] Thus, the sum of the interior angles of a polygon with 40 sides is **6840 degrees Read more....tinyurl com/22enuvst
What is the measure of one angle regular polygon with 9 sides?
Method 1: Interior angles of regular n-sided polygon are ((2n - 4) x 90)/n degrees When n = 9 this works out at 140 degrees. Method 2: Exterior angles of regular n-sided polygon are 360/n degrees in this case 40 degrees, making interior angles 180 - 40 ie 140 degrees.
How many sides does a regular polygon have if it has an interior angel of 171?
Interior angle = 180n - 360 = 171n so 9n = 360 and your polygon has 40 sides. This works because the interior angles of any n-sided polygon total 180n - 360 degrees, usually expressed as "(2n - 4) right angles"
What is the size of each interior angle in a regular 40-sided polygon?
In a regular 40-sided polygon (also known as a tetracontagon), each interior angle can be calculated using the formula ((n-2) \times 180^\circ / n), where (n) is the number of sides. For a 40-sided polygon, this yields ((40-2) \times 180^\circ / 40 = 38 \times 180^\circ / 40 = 171^\circ). Therefore, each interior angle in a regular 40-sided polygon measures 171 degrees.
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
What is the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 6840 degrees
What is the number of angles if the sum of the interiors angles are 40?
No polygon can have a sum of interior angles less than 180 degrees.
