The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945
Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.
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Opinion #2:
-- There are 36 possible outcomes when 2 dice are rolled.
-- Only one of the outcomes is a 2.
-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .
-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .
-- The 'odds' are 1,011 to 989 against it.
Odds of rolling ONE six - 6:1 Odds of rolling TWO sixes - 36:1 Odds of rolling two sixes, SIX times - 216:1
The probability of rolling a 3 on a die are 1/6. Since each roll is an independent event, the probability of rolling a 3 4 times in a row is (1/6)4 or 1/1296.The odds of something happening are the chances of it happening vs. the chances of it not happening. The chance of not rolling a 3 4 times in a row is 1-(1/1296) or 1295/1296.Therefore the odds are 1:1295
Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = 0.00463 The probability of rolling six three times in a row eventually is 1 (ie a certainty).
The probability of rolling 7 once with two dice is 1 in 6, o 0.1667. The probability, then, of doing that twice in a row is 1 in 36, or 0.02778.
The chance that one dice falls on 6 is 1 out of 6. The probability that dice falls twice in a row is 1 out of 6 and 1 out of 6, that is (1/6)(1/6)=(1/6)^2=1/36.Hence the probability of six sixes in a row is(1/6)^6=1 out of 46,656.
The odds of rolling a 7 are 1/6. The odds of rolling two in a row are 1/36. The odds of rolling an 11 are 1/18. The odds of rolling two in a row are 1/324. The odds of rolling doubles are 1/6. The odds of rolling double twice in a row are 1/36.
The odds of rolling snake eyes (two ones) on a pair of dice is 1 in 36, since there are 36 possible outcomes when rolling two dice. To find the odds of rolling snake eyes twice in a row, you multiply the probabilities: ( \frac{1}{36} \times \frac{1}{36} = \frac{1}{1296} ). Therefore, the odds of rolling snake eyes twice in a row are 1 in 1296.
1 in 12
The chance of throwing 7 with 2 dice is 1 in 6. The chance of throwing 7 with 2 dice 56 times in a row is 1 in 656 ≈ 1 in 3.771 x 1043.
Odds of rolling ONE six - 6:1 Odds of rolling TWO sixes - 36:1 Odds of rolling two sixes, SIX times - 216:1
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
The probability of rolling doubles with 2 dice is 1 in 6, or about 0.1667. The probability of doing that 100 times in a row is 0.1667100 or about 1.531x10-78.
The probability of rolling a 3 on a die are 1/6. Since each roll is an independent event, the probability of rolling a 3 4 times in a row is (1/6)4 or 1/1296.The odds of something happening are the chances of it happening vs. the chances of it not happening. The chance of not rolling a 3 4 times in a row is 1-(1/1296) or 1295/1296.Therefore the odds are 1:1295
Rolling 2 twice in a row in the first two rolls is 1/6*1/6 = 1/36. But rolling 2 twice eventually is as close to certainty as you can get.
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
1/6 x 1/6 x 1/6 = 1/216 is the odds of getting three doubles in a row so I suppose the odds of not rolling three in a row is 215/216 or 99.54% chance.
Assuming fair dice: With 3 dice there are 6 x 6 = 36 possible permutations (the two dice can be identified and are independent of each other). Of these there are 3 ways (1+3, 2+2, 3+1) of getting four. Probability of getting a four with 2 dice on one roll = 4/36 = 1/9 As rolls are independent, the probability of getting 4 with 2 dice 3 times in a row is 1/9 x 1/9 x 1/9 = 1/729 So the odds of it are 728 to 1 against, ie 1 in 729 or about 0.14 %.