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What are the possible variations of a 5 digit sequence using 1-6 when 345 are the first 3 digits?
Wiki User
∙ 9y ago
if the repetition is not allowed then the arrangement can be 3*2*1 = 6 ways
if repetition is allowed the ways can be 6*6*6= 216 ways
Wiki User
∙ 9y ago
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What are the possible sequence variations of a 5 digit sequence using the numbers 1 to 6 when the first 3 digits in the sequence are 345?
if repeating is allowed... 36 (6x6, for the last two digits) If not, 6 (3x2, last two digits)
What are the possible sequence variations of a 3 digit number?
3!=6
The largest 12- digit number where repeated digits are allowed?
If repeated digits are allowed, then the largest 12-digit number is 999,999,999,999 .If repeated digits are not allowed, then the largest 12-digit number is 989,898,989,898 .If the same digit can't be used more than once, then the largest possible number has only10 digits. The number is 9,876,543,210 .
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
How many different sequences of 4 digits are possible if the first digit must be 3 4 or 5 and if the sequence may not in 000?
Assuming the the last part of the question is that the sequence may not END in 000, there are 2997 sequences.
How many 5 digit numbers are there with distinct digits?
There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices
How many different three digit palindromes can you make using only the digits 1and 2?
There are two possible digits for the first and last digit, and two possible digits for the centre digit, making 2 × 2 = 4 possible 3 digit palindromes from the set {1, 2}, namely the set {111, 121, 212, 222}.
How many different sequences are the in a 7 digit number?
10 digits to select for the first number in the sequence 10 digits to select for the second number in the sequence for each possible option of 10 digits in the first slot in the sequence (10 * 10) 10 digits to select for the third number in the sequence for each possible option of 10 digits in the second slot for each possible digit in the first slot of the sequence (or more easily put, 10 possible digits for each of 100 potential first two number sequences) [10*10*10] etc.... =10 * 10 * 10 * 10 * 10 * 10 * 10 = 10^7 = 10,000,000 (10 Million) Now add an area code before that 7 digit phone number and you get 10 Billion combinations (of course there are exclusions such as any sequence starting in 911 would be prohibited which is a reduction of 10 million numbers itself - 911 000 0001, 911 000 0002, etc. There are many other exclusions as well such as can't start with 0 - this removes another 1 billion sequences)
How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
What is the greatest possible 9 digit number that uses each of the digits 1-3 times?
what is the greets possible 9 digit number that uses each of the digits 1-3 times
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many even four digit numbers can be made using 02356 where the first digit is cannot be 0 and no digits are repeated?
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
