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equation1: y+1 = x => y = x-1

equation 2: y = x2-6x++5

If, x2-6x+5 = x-1 then, x2-7x+6 = 0, solving this quadratic equation, x = 1 or x = 6

Substituting into equation 1: when x = 1, y = 0 and when x = 6, y = 5

Therefore the solutions are: x = 1, y = 0 and x = 6, y = 5

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Q: What are the solutions for the simultaneous equation y plus 1 equals x and y equals x squared - 6x plus 5?
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