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How many real solutions are there to the equation 4x2 plus x 1 equals 0?
If you mean: 4x2 + x - 1 = 0 then: 4x2 + x = 1 x2 + x/4 = 1/4 x2 + x/4 + 1/64 = 17/64 (x + 1/2)2 = 17/64 x + 1/2 = ± √17 / 8 x = (-4 ± √17) / 8 Giving us two real solutions. If on the other hand you mean: 4x2 + x + 1 = 0 Then: 4x2 + x = -1 x2 + x/4 = -1/4 x2 + x/4 + 1/64 = 15/64 (x + 1/2)2 = 15/64 x + 1/2 = ± √15 / 8 x = (-4 ± √15) / 8 Again, giving us two real solutions.
What are the x-solutions for the equation 10x2-64 equals 36 plus 6x2?
If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5
What are the x solutions for 10x2-64 equals 36x plus 6x2?
10x2 - 64 = 36x + 6x2Subtract 6x2 from both sides:4x2 - 64 = 36xSubtract 36x from both sides:4x2 - 36x - 64 = 0Divide everything by 4:x2 - 9x - 16 = 0Use the quadratic formula:x = (9±√(92-4(-16)))/(2)x = (9-√(145))/2 or x = (9+√(145))/2
How do you solve the quadratic equation -4y2 32y-64?
Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign If so then by using the quadratic equation formula the values of y both equal 4
How many solutions 4x2 plus 8x plus 3 equals 0?
Start with the equation 4x2 + 8x + 3 = 0. Invoke the quadratic equation: x = [-b ± √(b2 - 4ac)]/2a, where a = 4, b = 8, and c = 3. Plug in the values for a, b, and c and solve: x = [-8 ± √(82 - 4*4*3)]/2*4, x = [-8 ± √(64 - 48)]/8, x = -1 ± √(16)/8, x = -1 ± 1/2, x = {-1/2, -3/2}.
What are the x solutions for the equation 4x2-30 equals 34?
4x2 - 30 = 34 ⇒ 4x2 = 64 ⇒ x2 = 16 ⇒ x = 4 or -4
What are the x solutions for the equation 10x2 - 64 equals 36 plus 6x2?
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
How many real solutions are there to the equation 4x2 plus x 1 equals 0?
If you mean: 4x2 + x - 1 = 0 then: 4x2 + x = 1 x2 + x/4 = 1/4 x2 + x/4 + 1/64 = 17/64 (x + 1/2)2 = 17/64 x + 1/2 = ± √17 / 8 x = (-4 ± √17) / 8 Giving us two real solutions. If on the other hand you mean: 4x2 + x + 1 = 0 Then: 4x2 + x = -1 x2 + x/4 = -1/4 x2 + x/4 + 1/64 = 15/64 (x + 1/2)2 = 15/64 x + 1/2 = ± √15 / 8 x = (-4 ± √15) / 8 Again, giving us two real solutions.
What are the x-solutions for the equation 10x2-64 equals 36 plus 6x2?
If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5
What are the x solutions for 10x2-64 equals 36x plus 6x2?
10x2 - 64 = 36x + 6x2Subtract 6x2 from both sides:4x2 - 64 = 36xSubtract 36x from both sides:4x2 - 36x - 64 = 0Divide everything by 4:x2 - 9x - 16 = 0Use the quadratic formula:x = (9±√(92-4(-16)))/(2)x = (9-√(145))/2 or x = (9+√(145))/2
What are the x-solutions for 4x2 - 30 equals 34?
4x8=32 32x2=64 64-30=34 X=8
How do you solve the quadratic equation -4y2 32y-64?
Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign If so then by using the quadratic equation formula the values of y both equal 4
How many solutions 4x2 plus 8x plus 3 equals 0?
Start with the equation 4x2 + 8x + 3 = 0. Invoke the quadratic equation: x = [-b ± √(b2 - 4ac)]/2a, where a = 4, b = 8, and c = 3. Plug in the values for a, b, and c and solve: x = [-8 ± √(82 - 4*4*3)]/2*4, x = [-8 ± √(64 - 48)]/8, x = -1 ± √(16)/8, x = -1 ± 1/2, x = {-1/2, -3/2}.
What are the solutions for 4x2 - 30 equals 34?
4x² - 30 = 34 4x² = 34 + 30 4x² = 64 4x = √64 4x = 8 x = 8 ÷ 4 x = 2
What are the x solutions for 4x²-30 equals 34?
4x2 - 30 = 34 Add 30 to both sides 4x2 = 64 Divide both sides by 4 x2 = 16 Take the square root of both sides: x = 4 or -4
Which choiceshows 4x square -30 equals 34?
4x2-30 = 34 4x2 = 34+30 4x2 = 64 x2 = 16 x = 4
What are the solutions for 10x2-64 equals 36 plus 6x2?
10x2 - 64 = 36 + 6x2 Combine like terms: 4x2 = 100 Divide both sides by 4: x2 = 25 Take square roots: x = -5 or +5
