Start with the equation 4x2 + 8x + 3 = 0.
Invoke the quadratic equation:
x = [-b ± √(b2 - 4ac)]/2a, where a = 4, b = 8, and c = 3.
Plug in the values for a, b, and c and solve:
x = [-8 ± √(82 - 4*4*3)]/2*4,
x = [-8 ± √(64 - 48)]/8,
x = -1 ± √(16)/8,
x = -1 ± 1/2,
x = {-1/2, -3/2}.
2.
4x2 plus 3=11
4x2+49x+90 = (4x+9)(x+10) when factored
dont know sorry
-((4x + 1)(x - 1))
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.
2.
It has 2 real solutions because the discriminant is greater than zero.
4x2 plus 3=11
y=4x2+3x+8
Using the quadratic equation formula:- x = -0.5447270865 or x = 2.294727086
4x2+49x+90 = (4x+9)(x+10) when factored
4x2 - 30 = 34 ⇒ 4x2 = 64 ⇒ x2 = 16 ⇒ x = 4 or -4
4x2 = -12x, divide both sides by 4x: x = -3
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
No.
dont know sorry