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Sum of first n integers is n/2 times n + 1 ie 27.5 x 56 which is 1540

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Q: What are the sum of the integers from 1 to 55?
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Related questions

What is the sum of integers from 1 10?

55


What are the integers if The sum of two integers is -1 the product of these integers is -56?

55


Is 55 the sum of the first positive 10 integers?

Yes. The sum of 1 to 10 (inclusive) is 55.


What is the sum of the integers from 1 to 10?

55 Basically the sum of al integers from 1 to n is Sn=(n²+n)/2 (Think why is this number always an integer!)


What is the sum of the first ten positive integers?

The sum of the first ten positive integers is: 55


What are 2 consecutive integers that have the sum of 112?

The numbers are 55, and 57. Two consecutive integers have an odd sum.


What is the sum of the 10 positive integers?

The sum of the first 10 positive integers, using the formula N1 + (N1 + 1) + ... + N2 = N2 * (N2 + 1) / 2 - (N1 - 1) * N1 / 2 is: 55


What is the sum of the first ten negative integer and the first ten positive integer?

The sum of the first ten positive integers, i.e. 1,2,3,4,5,6,7,8,9, and 10, is 55. The sum of the first ten negative integers, i.e. -1,-2,-3,-4,-5,-6,-7,-8,-9, and -10 is -55. The sum of the first ten positive integers plus the sum of the first ten negative integers is 0.


What is the sum off all integers from -10 to 2012 inclusive?

sum -10 to -1 = -55; sum 1 to 2,012 = 2,013 x 1,006 = 2,025,078 total 2,025,023


The sum of two consecutive integers is less than 55?

Let the two consecutive integers be n and n+1. Then, n + (n + 1) < 55 2n + 1 < 55 2n < 55 - 1 : 2n < 54 n < 27 The Inequality Statement can therefore be modified to show that for two consecutive integers to be less than 55 then the smaller integer must be less than 27.


The sum of four consecutive odd integers is 216?

The integers are 51, 53, 55 and 57.


What is the sum of all the consecutive numbers between 1 and 10?

Assuming the question refers to INTEGERS and not numbers, the answer is 55.