Call the small number X and the larger one X+1. Sum of the first and three times the second is 55: X + 3(X+1) = 55; simplify and solve for X: X=13. So the integers are 13 and 14.
I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.
The integers are 5 and 7.
They are 5 and 6 because 5+(2*6) = 17
4+(6+6) All these words in mathematics are represented by an equation. Write and solve it to find those integers. If the first integer is x, the second one will be x + 2 (since consecutive even integers differ by 2). So we have: x + 2(x +2) = 16 x + 2x + 4 = 16 3x + 4 = 16 subtract 4 from both sides 3x = 12 divide by 3 both sides x = 4 Thus the integers are 4 and 6.
2 times 30+31+32+33 41+42+43
10-11-12
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
18, 20 and 22
Their sum is 99.
They are 14, 16 and 18.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The numbers are 14, 16 and 18.
The sum of three consecutive integers is -72
The integers would begin with 10.
1, 2 and 3 -1, -2, and -3 6 or -6
i dont now