Sum of first n integers is n/2 times n + 1 ie 27.5 x 56 which is 1540
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The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0
The sum of the first ten positive integers is: 55
Call the small number X and the larger one X+1. Sum of the first and three times the second is 55: X + 3(X+1) = 55; simplify and solve for X: X=13. So the integers are 13 and 14.
what is the sum of the first 10 positive integers? To me, if you include 0 as the first integer, then the tenth integer is 9 and the sum is 45. If you don't include 0, the tenth integer is 10, and the sum is 55.
(300 x (300 + 1)) / 2 = 45150 Therefore, the sum of all the integers from 1 to 300 is 45150.