6,12,18.
Yes, the product of any three consecutive numbers is divisible by 6. This is because among any three consecutive integers, at least one of them is even (ensuring divisibility by 2), and at least one of them is divisible by 3. Since 6 is the product of 2 and 3, the product of any three consecutive numbers is therefore divisible by 6.
The integers are 6, 8 and 10.
The integers are -6, -5 and -4 OR -7, -5 and -3 using only consecutive odd integers.
They are -6, -5 and -4.
-6, -7, and -8.
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
yes always this is true' example 1,2,3 sum is 6 and is divisible by 3
Here are some consecutive odd integers. All must follow this form: x+x+2+x+2=3x + 6 6 is divisible by 3. So is 3x. If you add two integers that are divisible by 3, it is still divisible by three. The question is not about odd integers, but consecutive integers. This should be x + x+1 + x+2 =3x+3 A bit simpler would be the three in a row : x-1, x, x+1 which add up to 3x which can be divided by 3.
2 4 6
The integers are 6, 8 and 10.
The integers are -6, -5 and -4 OR -7, -5 and -3 using only consecutive odd integers.
Because 6*8 = 48 and 48/8 = 6
They are -6, -5 and -4.
The numbers are -6, -5 and -4.
4, 5, and 6 are.
-6, -7, and -8.
The numbers are 6, 7 and 8.