Q: What are the whole numbers in 3x(2 plus 5)?

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x3 + 3x2 - 9x + 5 = 0 has roots of -5,1 and 1. CHECK : x3 + 3x2 - 9x + 5 = (x + 5)(x - 1)(x - 1)

(3x2)+5=11

(x + 1)(3x + 5)

3x2+13x-10 = (3x-2)(x+5) when factored

If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3

x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2

That factors to (x + 5)(3x + 2)

= (3x + 5)(x + 1) so x = -5/3 or -1

x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0

(x + 4)(3x - 5)