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y=x2+4x+1
3
No. x2 -4x - 12 = (x + 2)(x - 6)
x2-4x-12 = (x-6)(x+2) when factored
-2, 6
x=2,-6 x^2+4x-12 (x^2-2x)(+6x-12) x(x-2)+6(x-2) (x-2)(x+6)=0
x2 + 4x - 96 = (x - 8)(x + 12).
The vertex of the positive parabola turns at point (-2, -11)
Y = X2 - 4X + 12 set to 0 X2 - 4X + 12 = 0 subtract 12 from each side X2 - 4X = - 12 now, take the linear term ( - 4 ), halve it, square it and add it to both sides X2 - 4X + 4 = - 12 + 4 factor the left side, gather terms on the right (X - 2)2 = - 8 add 8 to each side (X - 2)2 + 8 = 0 ------------------------ (2, 8) ------------the vertex of this function
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
4x-x2 = 2
x2+4x-12 = (x-2)(x+6) when factored