If: y = 4x^2 -12x -3 and y = x^2 +11x +5
Then: 4x^2 -12x -3 = x^2 +11x +5
Transposing terms: 3x^2 -23x -8 = 0
Factorizing: (3x+1)(x-8) = 0 => x = -1/3 or x = 8
Therefore the x coordinates are: -1/3 and 8
The x coordinates are -1/3 and 24.
They intersect at the point of: (-3/2, 11/4)
They touch each other at (0, 100) on the x and y axis.
If: y = 1 -x^2 -8x -16 and y = x^2 +3x -10 Then: x^2 +3x -10 = -x^2 -8x -15 Or: 2x^2 +11x +5 = 0 Factorizing the above: (2x+1)(x+5) = 0 meaning x = -1/2 or x = -5 When x = -1/2 then by substitution y = -45/4 When x = -5 then by substitution y = 0 Therefore it follows coordinates of intersection are at: (-1/2, -45/4) and (-5, 0)
If: y = 5x^2 -2x +1 and y = 6 -3x -x^2Then: 5x^2 -2x +1 = 6 -3x -x^2Transposing terms: 6x^2 +x -5 = 0Factorizing: (6x -5)(x +1) = 0 => x = -1 or x = 5/6Through substitution points of intersect are at: (-1, 8) and (5/6, 101/36)
If you mean the graph, then the lowest coordinates would be (0,0). Also known as the origin.
They intersect at the point of: (-3/2, 11/4)
Because when collated together the discriminant of b2-4ac = -32 i.e. 144-(4*2*22) = -32 In order for the parabolas to make contact with each other the discriminant must equal zero or be above zero.
The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)
If you mean the coordinates of the line x-y = 2 that intersects the curve of x2-4y2 = 5 Then the coordinates work out as: (3, 1) and (7/3, 1/3)
They touch each other at (0, 100) on the x and y axis.
If: y = 1 -x^2 -8x -16 and y = x^2 +3x -10 Then: x^2 +3x -10 = -x^2 -8x -15 Or: 2x^2 +11x +5 = 0 Factorizing the above: (2x+1)(x+5) = 0 meaning x = -1/2 or x = -5 When x = -1/2 then by substitution y = -45/4 When x = -5 then by substitution y = 0 Therefore it follows coordinates of intersection are at: (-1/2, -45/4) and (-5, 0)
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then the length of the line works out as: 65/18 or 3.6111 ... recurring decimal 1
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
If: y = 5x^2 -2x +1 and y = 6 -3x -x^2Then: 5x^2 -2x +1 = 6 -3x -x^2Transposing terms: 6x^2 +x -5 = 0Factorizing: (6x -5)(x +1) = 0 => x = -1 or x = 5/6Through substitution points of intersect are at: (-1, 8) and (5/6, 101/36)
If you mean the graph, then the lowest coordinates would be (0,0). Also known as the origin.
There is no connection between the given curves because when they are combined into a single quadratic equation the discriminant of the equation is less than zero which means they share no valid roots.
type you answer here!