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Q: What are the x intercepts of y equals 2x2 3x 20?

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2x2 + 3x - 20 = (x + 4)(2x - 5).

y = 0 gives 0 = - x - 20 so that x = -20 So the intercept is (-20, 0)

No.

2X2 = 3Xset to 02X2 - 3X = 0factorX(2X - 3) = 0zero factor rule2X = 3 = 02X = 3X = 3/2======X = 0X = 3/2

(-2,-1)

Related questions

how do you factor y=2x^2+3x-20 to get the roots

y = 2x2 - 3x - 20 ∴ y = 2x2 - 8x + 5x - 20 ∴ y = 2x(x - 4) + 5(x - 4) ∴ y = (2x + 5)(x - 4) The x intercepts occur when y = 0, which happens when either of the two factors on the left side of the equation equal zero. This means that they are at the points (-5/2, 0) and (4, 0).

2x2 + 3x - 20 = (x + 4)(2x - 5).

2x2 equals 5

y = 0 gives 0 = - x - 20 so that x = -20 So the intercept is (-20, 0)

No.

If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2

2X2 = 3Xset to 02X2 - 3X = 0factorX(2X - 3) = 0zero factor rule2X = 3 = 02X = 3X = 3/2======X = 0X = 3/2

(-2,-1)

X intercept: -5 Y intercept: +3

x=20 y=-3

The discriminant is 1.