Q: What are three consecutive numbers that add up to 68?

Write your answer...

66 68 70 ------ 204

They are: 68+69+70 = 20768, 69 and 70.

137

The three numbers will have a mean of 204/3 = 68. The two numbers are therefore 66, 68, 70.

66 + 67 + 68

5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 = 68

Answer: The even numbers are 62, 64, 66, and 68

64 + 66 + 68 = 198

The numbers are 33 and 35.

33 & 35.

The idea is to add all three numbers, then divide the result by 3 (because there are 3 numbers).

67 + 68 + 69 = 204

207

Here's how you can work it out: First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say: x + (x + 2) + (x + 4) = 210 ∴ 3x + 6 = 210 ∴ 3x = 204 ∴ x = 68 We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together: 68 + 70 + 72 = 210 which confirms our answer.

The GCF of 68 and 70 is 2. The GCF of any two consecutive even numbers is 2.

You need 5: 60, 62, 64, 66 & 68

-66 and -68

60, 62, 64, 66, 68

The numbers are 60, 62, 64, 66 and 68.

Three numbers go into 68. Two goes in twice and seventeen goes in once.

to find the mean of a group of numbers, add them together and divide by the number of numbers there are in that group. in this case there are 6

"Consecutive integers of -204" doesn't really make sense; -204 is just a single integer.

How about: 2*2*17 = 68 as a product of its prime factors

Call the numbers: x, (x+1), and (x+2)The sum is: x + (x+1) + (x+2) = 3x + 3 = 2073x = 204x = 68The numbers are 68, 69, and 70.

43, 23 and 2