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I'll represent the smaller number with the variable 'n'. Now, how much larger must the second number be?

The consecutive odd integers starting at 1:

1,3,5,7,9,11,13...

You can see that each number is two more than the last number. Therefore, we know that the larger number must be 2 more than 'n', or n+2. Finally, use the last piece of information that you are given to solve the problem.

1st number + 2nd number = 130

n + n+2 = 130

2n + 2 = 130

2n + 2 - 2 = 130 - 2

2n = 128

2n/2 = 128/2

n = 64

This is the first number, and so we know that because the second number is 2 more than the second number, the second number must be 64+2, or 66.

n+2 = 64 + 2

n + 2 = 66

The two integers are 64 and 66

You can check to see if this is correct.

64 + 66 =? 130

130 = 130

This is correct.

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Q: What are two consecutive odd integers that have a sum of 130?
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