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I'll represent the smaller number with the variable 'n'. Now, how much larger must the second number be?
The consecutive odd integers starting at 1:
1,3,5,7,9,11,13...
You can see that each number is two more than the last number. Therefore, we know that the larger number must be 2 more than 'n', or n+2. Finally, use the last piece of information that you are given to solve the problem.
1st number + 2nd number = 130
n + n+2 = 130
2n + 2 = 130
2n + 2 - 2 = 130 - 2
2n = 128
2n/2 = 128/2
n = 64
This is the first number, and so we know that because the second number is 2 more than the second number, the second number must be 64+2, or 66.
n+2 = 64 + 2
n + 2 = 66
The two integers are 64 and 66
You can check to see if this is correct.
64 + 66 =? 130
130 = 130
This is correct.
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