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I'll represent the smaller number with the variable 'n'. Now, how much larger must the second number be?
The consecutive odd integers starting at 1:
1,3,5,7,9,11,13...
You can see that each number is two more than the last number. Therefore, we know that the larger number must be 2 more than 'n', or n+2. Finally, use the last piece of information that you are given to solve the problem.
1st number + 2nd number = 130
n + n+2 = 130
2n + 2 = 130
2n + 2 - 2 = 130 - 2
2n = 128
2n/2 = 128/2
n = 64
This is the first number, and so we know that because the second number is 2 more than the second number, the second number must be 64+2, or 66.
n+2 = 64 + 2
n + 2 = 66
The two integers are 64 and 66
You can check to see if this is correct.
64 + 66 =? 130
130 = 130
This is correct.
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What are three consecutive odd integers whose sum is 13?
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What is the sum of two consecutive odd integers is 116?
The two odd integers are 57 and 59.
Two consecutive odd integers whose sum is 36?
17 (odd integer) + 19 (odd integer) = 36 17 and 19 are consecutive odd integers.
The sum of two consecutive odd integers?
Are not all integers spaced out to be odd then even then odd then even etc (eg 1,2,3,4,5,6,7,8,9,10, etc) and therefore there is no such thing as two consecutive odd integers.
What are two consecutive odd integers if the sum of them is 32?
The integers are 15 and 17.
