I call it a multiple of 720.
Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.
Because 10 is divisible by both 2 and 5
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
No. (Example.....10 / 2 = 5, but 10 / 4 = 2.5)
10 is divisible by both 5 and 2, as are any multiples of 10.
If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10
It is divisible by 2, 5 and 10 but not the rest.
Prime numbers are only divisible by 1 and themselves. So, a prime number cannot be divisible by 10. The only prime number that is divisible by 2 is 2 itself; all other numbers divisible by 2 are not prime numbers.
If a number is divisible by 10 (i.e. 100) then it is also divisible by 5. Ex: 100 by 10, is 10 by 5, is 20 20 by 10 is 2 by 5 is 4 The number of times it is divisible by 5 will always be double the number of times it is divisible by 10, which makes sense because 10 is double 5.
An even number is a number divisible by 2, therefore 4,6,8, 10, etc. are all even numbers because they are divisible by 2. So, is 2 divisible by 2? Yes...
Yes.
No, it is not a prime. It is divisible by 11.