y4Improved Answer:-y2+y2 = 2y2
2y2-2y-4 = (2y-4)(y+1) when factored
It is a cubic function of y.
2(y^2 + 3y - 2)
2(y - 3)(y - 10)
y2 + y2 = 2y2
10x2y2 + 8xy2 - 210y2 = 2y2(5x2 + 4x - 105) = 2y2(5x2 + 25x - 21x - 105) = 2y2(x + 5)(5x - 21).
The y-intercept is the place (or places) where x=0 . So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero, and those are your y-intercepts.
All six of them
4 plus 8 plus 12 plus 16 is equal to 40.