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Some plusses or minusses would help, but here goes anyway:

2y2 - 6y - 8 = (2y + 2)(y - 4); y = -1 or 4

2y2 + 6y - 8 = (2y - 2)(y + 4); y = 1 or -4

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Q: Use the quadratic formula to solve 2y2 6y 8 equals 0?
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