The y-intercept is the place (or places) where x=0 .
So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero,
and those are your y-intercepts.
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2(y^2 + 3y - 2)
2(y - 3)(y - 10)
It works out that the centre of the circle is at (-0.5, 1.5) and its diameter is the square root of 28
Question: x = 2y2 +3 if x = 53 what NEGATIVE value of y makes this an equality Answer: x= 2y2 + 3 53 = 2y2 + 3 53 - 3 = 2y2 50/2 = y2 25 = y2 Take the Square Root of Both sides so we can get: y = Square root of 25 so: y = EITHER 5 or -5 Then the ANSWER is -5 (since we need the NEGATIVE Value of Y)
10x2y2 + 8xy2 - 210y2 = 2y2(5x2 + 4x - 105) = 2y2(5x2 + 25x - 21x - 105) = 2y2(x + 5)(5x - 21).