2ay2 + 5ay - 3a = a(2y2 + 5y - 3) = a(2y - 1)(y + 3)
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
The LCM is 72y^3.
6x^3y^2
you may use perfect square as shown below. 2y2+3y = -e-x+ex+5 2(y2+2(3/4)y + 9/16)-9/8 = -e-x+ex+5 2(y+3/4)2 = -e-x+ex+5 (y+3/4)2 = (-e-x+ex+5)/2 y+3/4 = +-((-e-x+ex+5)/2)1/2 y=+-((-e-x+ex+5)/2)1/2 -3/4
Yes, 18y3 + 2y2 + 1 is a polynomial; it is a cubic expression. If it were expanded to form an equation, then it would be a cubic equation (or higher), capable of solution.
The y-intercept is the place (or places) where x=0 . So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero, and those are your y-intercepts.
1
2(y - 3)(y - 10)
this equals to 12
y2 + y2 = 2y2
10x2y2 + 8xy2 - 210y2 = 2y2(5x2 + 4x - 105) = 2y2(5x2 + 25x - 21x - 105) = 2y2(x + 5)(5x - 21).
All six of them
2ay2 + 5ay - 3a = a(2y2 + 5y - 3) = a(2y - 1)(y + 3)
72y^3
5(x + 2y2)(x2 - 2xy2 + 4y4)
12y3 - 30y2 + 12yFactor out a y:y(12y2 - 30y + 12)Factor out a 6:6y(2y2 -5y + 2)Factor 2y2 - 5y + 26y(2y - 1)(y - 2)