first the two numbers have the same radicand which is radical 2 so we just add the numbers before them to become 7 radical 2
factor the 18. 18=2x3x3. Take out the 3 because it is squared. 5x3 radical 2=15radical2
9*radical(3)/2 = 4.5*radical(3) = 7.794 approx.
36
4 x2
2 radical 30
3
3
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
3^3*radical(128) = 3^3*radical(2^7) = 3^3*radical(2^6*2) =3^3*2^3*radical(2) = 216*radical(2).
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30
√2 x √2 = (√2)2 = 2
2
Ahh ok radical 40 is equal to 2 radical 10
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
A Huge ASS
radical(14)*radical(2) = 2*radical(7) Without further information available we will consider only the square roots. The square roots of 14 are +3.741 and -3.741, similarly the square roots of 2 are+1.414 and -1.414 and so we can have four products 1) (+3.741) X (+1.414) = +5.155 2) (-3.741) x (+1.414) = -5.155 3) (+3.741) x (-1.414) = -5.155 4) (-3.741) x (-1.414) = +5.155 Expressions 1 and 4 are equal, expressions 2 and 3 are equal. Hence the product of radical 14 times radical 2 can be +5.155 or -5.155