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How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
How do you show mathematically why a small increase in your vehicle's speed results in a tremendous increase in your vehicles kinetic energy?
The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.
How much work must be done on a 10 kilograms bicycle to increase its speed from 2 meters per second to 3 meters pe second?
When the bike is moving at 2 m/s, its kinetic energy is (1/2 m v2) = (5 x 4) = 20 joules.When it's moving at 3 m/s, its kinetic energy is (1/2 m v2) = (5 x 9) = 45 joules.The difference between initial KE and final KE is (45 - 20) = 25 joules.That's how much work you have to do on it in order to increase its KE.
How much work must be done on a 24 kg shopping cart to increase its speed from 1 m s to 4 m s?
Kinetic energy of a moving mass is [ 1/2 m V2 .Initial KE of the kart = (1/2) (24) (1)2 = 12 joules.Final KE = (1/2) (24) (4)2 = 192 joules.Difference = amount of energy due to increased speed = (192 - 12) =180 joules.
What are the two values of kinetic energy?
That can't be answered without the question but kinetic energy (KE) can be calculated like this: KE = 0.5mv2, where m is mass (kg) and v is velocity (m/s)
How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
Why is kinetic energy of an object four times larger when the speed doubles?
The expression for KE is 1/2 m v2 As v is doubled then KE will be 1/2 m (22) V2 So it becomes 4 times the original.
What are the kinematic equation of archery?
ke=M * v2 / 450,240 ke=Kinetic Energy M = mass (weight of arrow in grains)v = velocity of arrow in f.p.s.
What is the equation used to express the kinetic energy of a moving body?
KE = (1/2) m v2 Where KE = kinetic energy, m = the mass, and v is the speed.
Is vibration produce energy?
Yes. Vibration is movement and from the equation, KE = (1/2)*m*v2, where m is the mass, v is the velocity and KE is the kinetic energy, it therefore causes energy.
What type of effect does an objects speed have on its kinetic energy than a change in its mass?
KE = .5 m v2
What is the relationship between motion and energy?
The basic relationship for kinetic energy of a body is KE = ½ m v2. If the mass is in kg and the speed in metres/sec, the answer for the KE is in Joules.
What is the relationship pattern between kinetic energy mass and speed?
KE = 0.5 x m x v2, where m is mass in kg, and v is speed in m/s.
What is the kinetic energy of an odject that has a mass of 20 kilograms and a speed of 2.8?
Kinetic energy is given by 1/2 x M x V2. So if M = 20kg, and V= 2.8 meters/sec, V2 = 7.84, KE = 78.4 Joules.
How do you show mathematically why a small increase in your vehicle's speed results in a tremendous increase in your vehicles kinetic energy?
The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.
When mass and speed of a moving body are doubled what happens to its kinetic energy?
Momentum = (mass x velocity) = M V If velocity is doubled, then new momentum = (M x 2V) = 2 x (M V) = double the original momentum. ========================= Kinetic energy = 1/2 M V2 If 'V' is doubled, then new KE = (1/2 M) (2V)2 = (1/2 M) (4V2) = 4 (1/2 M V2) = 4 times original KE.
What is the kinetic energy of an object that has a mass of 20 kilograms and a speed of 2.8 m per s?
KE = 1/2 M V2 = 1/2 (20) (2.8)2 = 78.4 joules
