You have performed division. Not all numbers may be divided by all other numbers without leaving a remainder. A remainder is quite common to all division problems.
Example: 7 divided by 3 = ?
3 times 2 = 6 and 3 times 3 = 9
Since 9 is greater than seven we use 6
2 times 3 = 6
7 minus 6 = 1
but that leaves a remainder of 1
So, the answer is 2 remainder 1
If the divisor of a division problem is 4, any number between 0 and 3 (inclusive) can be a remainder for that problem.
It means that there is no remainder in the problem. For example 9/3=3. The nine is the dividend, and the first three is the divisor. There was no remainder, so it divided evenly.
It is: 329/6 = 54 remainder 5
Yes there is. The real problem is just inverting the remainder into the decimal for the answer.
remainder
If the divisor of a division problem is 4, any number between 0 and 3 (inclusive) can be a remainder for that problem.
6.6667
It means that there is no remainder in the problem. For example 9/3=3. The nine is the dividend, and the first three is the divisor. There was no remainder, so it divided evenly.
Yes the mean can have a remainder but the remainder would normally be either rounded or converted into a fraction.
I'm hoping that's "remainder." In Mathematics, the remainder is the number that is left over in a division problem in which one quantity does not exactly divide another: 23 divided by 3 is 7, remainder 2.
It is: 329/6 = 54 remainder 5
the parts of division problem are : dividend , divisor , quotient and remainder . where : dividend = quotient * divisor + remainder
You incorporate the fractional remainder into the mean. The mean does not have to be a whole number.
A prime number can not be divided, without a remainder, by any other number except itself and 1.
then do the oppsite.Multiply.
Yes there is. The real problem is just inverting the remainder into the decimal for the answer.
7.4