You have performed division. Not all numbers may be divided by all other numbers without leaving a remainder. A remainder is quite common to all division problems.
Example: 7 divided by 3 = ?
3 times 2 = 6 and 3 times 3 = 9
Since 9 is greater than seven we use 6
2 times 3 = 6
7 minus 6 = 1
but that leaves a remainder of 1
So, the answer is 2 remainder 1
If the divisor of a division problem is 4, any number between 0 and 3 (inclusive) can be a remainder for that problem.
It means that there is no remainder in the problem. For example 9/3=3. The nine is the dividend, and the first three is the divisor. There was no remainder, so it divided evenly.
It is: 329/6 = 54 remainder 5
Yes there is. The real problem is just inverting the remainder into the decimal for the answer.
remainder
If the divisor of a division problem is 4, any number between 0 and 3 (inclusive) can be a remainder for that problem.
6.6667
It means that there is no remainder in the problem. For example 9/3=3. The nine is the dividend, and the first three is the divisor. There was no remainder, so it divided evenly.
Yes the mean can have a remainder but the remainder would normally be either rounded or converted into a fraction.
I'm hoping that's "remainder." In Mathematics, the remainder is the number that is left over in a division problem in which one quantity does not exactly divide another: 23 divided by 3 is 7, remainder 2.
It is: 329/6 = 54 remainder 5
the parts of division problem are : dividend , divisor , quotient and remainder . where : dividend = quotient * divisor + remainder
A prime number can not be divided, without a remainder, by any other number except itself and 1.
You incorporate the fractional remainder into the mean. The mean does not have to be a whole number.
then do the oppsite.Multiply.
Yes there is. The real problem is just inverting the remainder into the decimal for the answer.
Multiply the quotient times the dividend and then add on the remainder to the product.