It means N times N. 3 squared is 9.
Simple equation lad. In your example, you said n=4 and x= n squared + n - 1 + (n-2)squared + (n-3)squared. You simply write n²+n-1+(n-2)²+(n-3)² I hope that is what you mean by what you say. P.S. To get the to the power of sign, hold alt and press 0178 for ², and 0179 for ³
If that's n squared, the multiples are n squared, 2 n squared, 3 n squared and so on. If that's n + 2, the multiples are n + 2, 2n + 4, 3n + 6 and so on.
3 squared is 9 and so 9n = 63 which means n = 7
n squared minus n
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
are you sure you don't mean "4n squared - 26n + 42" ?? This would give 2(2n-7)(n-3) Davehx
Take any positive integer n. If you square it, and subtract 1, you get (x squared - 1). If you take (n - 1) and (n + 1), and multiply them together, you get n squared - n + n - 1, which is the same as (n squared - 1).
If you mean n squared+11n+18 then it is (n+2)(n+9) when factored
It is 2n^3 + 7n^2 - 13n + 3
2 squared divided by 3 squared ie 4/9 in general, (a/b)^n = a^n/b^n . In this case (2/3)^2=2^2/3^2=4/9 Check: 2/3 = .667 squared = 0.444889; 4/9 =0.44444. Near enough!
answer is maths.
If you mean -(x^2) * x then the answer is -x^3 if you mean (-x)^2 * x then the answer is x^3
n2 + n2 = 2 n2
3(3n - 1)(n + 1)
Do you mean as in m3 it means 'cubed'
If you mean: (x+3) squared = (x+2) squared +11 Then the value of x works out as 3
Well take (2 squared by 3) that would 2 times 2 which is 4, times 2 which equals 8 so (2 squared by 3) eqauls 8
It is not an equation because it has no equality sign but it means xn squared-nx
No. Standard deviation is the square root of the mean of the squared deviations from the mean. Also, if the mean of the data is determined by the same process as the deviation from the mean, then you loose one degree of freedom, and the divisor in the calculation should be N-1, instead of just N.
Let n be the number. Then it's 3(n2 - 82).
3 squared=9 3 squared=3*3 3*3=9
The %d code is a printf format specifier that says to take the next argument and convert it into a decimal, based on an int. for (int i = -3; i < 4; ++i) printf ("i: %d i squared: %d\n", i, i*i); will print i: -3 i squared: 9 i: -2 i squared: 4 i: -1 i squared: 1 i: 0 i squared: 0 i: 1 i squared: 1 i: 2 i squared: 4 i: 3 i squared: 9 on stdout.
3 - 3 squared = 6 * * * * * NO! 3 - 3 squared = 3 - 9 = -6