That factors to (2n + 1)(n + 2)
104
n2+n3=n5 it's simple 8th grade pre-algebra
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
Obviously, both terms have the common factor "n". You get the other factor by dividing both terms by n. The result is "n + 2".
(n*n)+n
If you know the value of "n", you can replace it in the expression, then add. Otherwise, you have to keep them separate. You can still factor the expression, if you like, but that really won't make it any simpler.
Simple equation lad. In your example, you said n=4 and x= n squared + n - 1 + (n-2)squared + (n-3)squared. You simply write n²+n-1+(n-2)²+(n-3)² I hope that is what you mean by what you say. P.S. To get the to the power of sign, hold alt and press 0178 for ², and 0179 for ³
=n^2 +n =n(n+1) since either n or n+1 has to be even (consecutive numbers) the answer always is an even number
Add the x's squared together to get 2x^2+x. You cannot add anymore so the answer is 2x^2+x
n3 + 8n2 + 12n = n(n+2)(n+6)
That factors to (2n + 1)(n + 2)
104
(n - 4)(n - 12)
The surface area is length times width plus length. Then you find the square root of the width divided by two and then squared. You add this to the height squared plus the width. The width is multiplied by the square root of 1/2 squared plus the height squared.
No
It can't be factored because its discriminant is less than zero