(- 3, 10) and (6, 7)
Need slope.
m = Y2 - Y1/X2 - X1
m = 7 - 10/6 - (- 3)
= - 1/3
----------
Now, take that nice set of points, (6, 7), and use the point slope form.
Y - Y1 = m(X - X1)
Y - 7 = -1/3(X - 6)
Y - 7 = (- 1/3)X + 2
Y = (- 1/3)X + 9
==============The equation of the line
The straight line equation works out as: 3y = x
y=2/5x
The equation works out as: 5y = 2x or as y = 2/5x
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
When the equation represents a horizontal line.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
The straight line equation works out as: 3y = x
The straight line equation works out as: 3y = x
y=2/5x
Points: (14, 6) (21, 9) (7, 3) Slope of the line: 3/7 Equation of the line: 7y = 3x and it has no y intercept
The equation works out as: 5y = 2x or as y = 2/5x
Points: (3, 2) and (-9, 6) Slope: -1/3 Equation: 3y = -x+9
Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33
Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x