It will have 9 diagonals
In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
18
In a hexagon, each vertex can connect to all other non-adjacent vertices to form diagonals. Since a hexagon has 6 vertices, each vertex can form diagonals with the other 4 non-adjacent vertices. Therefore, each vertex of a hexagon can create 4 diagonals. This results in a total of 6 vertices x 4 diagonals = 24 diagonals in a hexagon.
The answer would be 18.
4.
110.Improved Answer:-It is 4
Either 12,14,16,or18 I think 18. * * * * * The correct answers is 4. You can draw only 3 diagonals from one vertex.
Obviously homework, so I'll give you some pointers:Assuming it is a regular hexagon then:Draw in all three diagonals of the hexagon - this will split the hexagon into 6 equilateral triangles.Sum the areas of the triangles to give the area of the hexagon.Use Pythagoras or trigonometric ratios to find the altitude of the triangles; the base of the triangles is the length of the side of the hexagon.
A hexagon can be divided into triangles by drawing diagonals from one vertex to all non-adjacent vertices. This results in a total of ( n - 2 ) triangles, where ( n ) is the number of sides in the polygon. For a hexagon, which has 6 sides, you can create ( 6 - 2 = 4 ) triangles. Thus, a hexagon can be divided into 4 triangles.
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
If the parallelogram happens to also be a rhombus (i.e. has all sides equal in length) then yes, otherwise no.
All quadrilaterals have 2 diagonals.