1 x 48, 2 x 24, 3 x 16, 4 x 12, 6 x 8 = 48
48 1/3, 48 2/3, 48 3/3
There are no two consecutive integers which sum to make 48. The closest you can get is if you drop the integer part of the problem and state simply that they have to have a difference of 1 between them. In which case it would be 23.5 and 24.5.
The two largest integers when multiplied together is 48 are 6 and 8. To get the single highest integer when multiplying it would be 1 and 48.
The integers are 44, 46 and 48.
The numbers are -18, -16 and -14.
The sum of two positive integers can never equal zero.
There are two consecutive even integers that equal -298: -150 and -148.
The integers are 106 and 108.
71
-17, -16 and -15
The numbers are 62 and 64 are two consecutive integers that equal 126.
No, the sum of two integers is not equal to the difference of the same two integers, except in specific cases. For two integers ( a ) and ( b ), the sum is ( a + b ) and the difference is ( a - b ). These two expressions can only be equal if one of the integers is zero or if they are equal (i.e., ( a = b )). In general, the sum will be greater than or less than the difference, depending on the values of ( a ) and ( b ).