If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.
The x and y intercepts are where a line on a graph intersects (crosses over) the x or y axis.
There is no limit to the number of y-intercepts a line can have. The axis itself is a line and it intercepts itself an infinite number of times.
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
y = -xBoth intercepts are at the origin. From there, the line slopes up to the leftand down to the right.
If 2 equations are perpendicular to one another they can have different y-intercepts, depending on how they are situated on a (x,y) graph.
If the slopes are different the lines are neither - they intersect. They are parallel or coincident if the slopes are the same. Then, if the y-intercepts are the same they are coincident while if the y-intercepts are different, they are parallel.
X intercept: -5 Y intercept: +3