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What is the greatest number of x- and y-intercepts that a circle can have?
A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.
How d yu find x and y intercept on a graph?
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
Find the x and y intercept of 9x54-6y?
I believe that you need an equation to solve for the x and y intercepts.
If the equation equal y x plus 4 is changed to y x-2 how would the graph of the equation change?
If you mean y = x+4 and y = x-2 then the slopes would be parallel but with different y intercepts
What is the x and y intercepts for 2x - y equals 8?
-6
What is the intercept of the equation y equals -x?
The 'x' and 'y' intercepts of that equation are both at the origin.
Find the x and y intercepts of 3x-2y6?
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
What is the greatest number of x- and y-intercepts that a circle can have?
A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.
What are the x and y intercepts for each equation?
To find the x and y intercepts of an equation, set y to 0 to find the x-intercept (solve for x), and set x to 0 to find the y-intercept (solve for y). For example, in the equation (y = 2x + 4), the x-intercept is found by setting (y = 0), giving (x = -2), and the y-intercept is found by setting (x = 0), yielding (y = 4). If you provide specific equations, I can calculate their intercepts for you.
How d yu find x and y intercept on a graph?
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
How to find the x-intercepts when there is no y?
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
Find the x and y intercept of 9x54-6y?
I believe that you need an equation to solve for the x and y intercepts.
What are the intercepts of the equation x4-2x2-8?
To find the intercepts of the equation (y = x^4 - 2x^2 - 8), we need to determine where the graph intersects the x-axis and y-axis. For the y-intercept, set (x = 0), yielding (y = -8), so the y-intercept is (0, -8). To find the x-intercepts, set (y = 0) and solve the equation (x^4 - 2x^2 - 8 = 0); this can be factored or solved using substitution methods, leading to the x-intercepts at approximately (x \approx 2.414) and (x \approx -2.414).
A linear equation cannot always be graphed by using intercepts alone?
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
How do how you determine the x intercepts from an equation?
The x-intercepts are obtained by solving the equation for those value of x for which y or f(x) = 0 : where f(x) is the equation of the curve or line. If f(x) is a straight line, and the equation is in the form y = mx + c, then y = 0 gives x = -c/m For a quadratic, of the form y = ax2 + bx + c, the x-intercents are the root sof the equation, ie [-b ± sqrt(b2 - 4ac)]/(2a). The intercepts are real only when the discriminant, b2 - 4ac is non-negative.
What are the intercepts of this line?
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
What is the formula to find the intercepts for a quadratic equation?
To find the intercepts of a quadratic equation in the standard form ( y = ax^2 + bx + c ), the y-intercept can be found by evaluating the equation at ( x = 0 ), which gives the point ( (0, c) ). For the x-intercepts, set ( y = 0 ) and solve the equation ( ax^2 + bx + c = 0 ) using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). The resulting values of ( x ) will give the x-intercepts.
