if is (x-6)-(1x-1) = -5
if id (x-6)-(1x+1) = -7
2x + 1 = 1x + 11Subtract 1x from each side:1x + 1 = 11Subtract 1 from each side:1x = 10
-1
1+1+x+x+x+y+y=2+3x+2y
-1x=5nSteps:3x-4x=5n like terms3-4=-1 add x -1x-1x=5n not like termsanswer -1x=5n
x6 + 3x4 - x2 - 3 = 0(x6 + 3x4) - (x2 + 3) = 0x4(x2 + 3) - (x2 + 3) = 0(x2 + 3)(x4 - 1) = 0(x2 + 3)[(x2)2 - 12] = 0(x2 + 3)(x2 + 1)(x2 - 1) = 0(x2 + 3)(x2 + 1)(x + 1)(x - 1) = 0x2 + 3 = 0 or x2 + 1 = 0 or x + 1 = 0 or x - 1 = 0x2 + 3 = 0x2 = -3x = ±√-3 = ±i√3 ≈ ±1.7ix2 + 1 = 0x2 = -1x = ±√-1 = ±i√1 ≈ ±ix + 1 = 0x = -1x - 1 = 0x = 1The solutions are x = ±1, ±i, ±1.7i.
If: x+1+2x = 1x+5 Then: x = 2
x = 0
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
incomplete formula.1x of 20 equals 2 = .10x is 0.1x?=2 ?=20
2x-1=-32x=-3+1x=-2/2x=-1
The 'answer' is the number that 'x' must bein order to make the statement true.x = -1
360