(2x + 1)(x + 1) so x = -0.5 or -1
2x2 + 3x + 1 = (x + 1)(2x + 1)
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
No.
y = 2x^(2) + 3x + 7 dy/dx = 2(2)x^(2-1) + 3(1)x^(1-1) + 7(0)x^(0-1) dy/dx 4x^(1) + 3x^(0) + 0 dy/dx = 4x + 3(1) dy/dx = 4x + 3 The answer!!!!! I have made a bit of 'heavy weather' of this but only to try and show you how it works out.
This expression could be reordered as 1 + 3x + 2x2.
No. You'd have to use the ABC-formula
2x2 equals 5
The discriminant is 1.
(x-1)(2x+5)
(3x - 1)(2x2 - 2x - 1)
-11
(2x - 1)(x - 1) so x = ½ or 1