(3x - 1)(2x2 - 2x - 1)
2x2 + 3x + 1 = (x + 1)(2x + 1)
2x2-3x-5 = (2x-5)(x+1) when factored
(x + 1) / (2x3 + 3x + 5) --- Can't depict long division here, but you can work this out by seeing if (x + 1) is a factor of (2x3 + 3x + 5). If it is, then the answer will be 1/(the other factor). In this case, that is true. (2x3 + 3x + 5)/(x + 1) = 2x2 - 2x + 5, so the term term above is equal to: 1 / (2x2 - 2x + 5)
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
No.
(x + 1)(2x - 5)
This expression could be reordered as 1 + 3x + 2x2.
(2x + 1)(x + 1) so x = -0.5 or -1
The discriminant is 1.
4x4 + 1 = (2x2 - 2x + 1)(2x2 + 2x + 1)
(x-1)(2x+5)