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Using the ordering rules of BODMAS:
Brackets
Of
Division
Multiplication
Addition
Subtraction
= 4 x 2 + 1
= 8 + 1
= 9
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∙ 14y ago
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What is 8x cubed plus 4x squared plus 6x plus 3?
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
What is the factorization of 4x2 plus 12x plus 5?
4x2 + 12x + 5 = (2x + 1)(2x + 5).
How do you factor -4x2 plus 3x plus 1 equals 0?
-((4x + 1)(x - 1))
Factorise 4xsquare plus 12x plus 5?
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
Factor completely 4x2 plus 4x plus 1?
(2x + 1)(2x + 1) or (2x + 1)2
What is 8x cubed plus 4x squared plus 6x plus 3?
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
What is 4x2-4x plus 1?
4x2-4x+1 = (2x-1)(2x-1)
What is 4x squared plus 5x plus 1 - 4x squared -6x simplified?
4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x
What is the factorization of 4x2 plus 12x plus 5?
4x2 + 12x + 5 = (2x + 1)(2x + 5).
Factor x3 plus 4x2 plus x plus 4?
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
Given 3x3 plus 4x2 plus x plus 7 is divided by x2 plus 1?
Given 3x3 + 4x2 +x + 7 is divided by x2 + 1, find the results:
Factor the trinomial 4x2 plus 24x plus 11?
The quadratic 4x2+24x+11 = (2x+1)(2x+11)
Factor 8x cubed plus 4x squared plus 6x plus 3?
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
How do you factor -4x2 plus 3x plus 1 equals 0?
-((4x + 1)(x - 1))
What is the factorization of 4x2 plus 6x plus 2?
2(x + 1)(2x + 1)
Factor 4x2 plus 8x plus 4?
4(x + 1)(x + 1)
Factorise 4xsquare plus 12x plus 5?
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
