(x + 3)(4x + 5)
5x^2 + 6x - 2 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-3 plus or minus the square root of 19) divided by 5. x = 0.2717797887081348 x = -1.4717797887081348
The factors of 25 are: 1, 5, 25 The factors of 35 are: 1, 5, 7, 35
That factors to 4(9x + 5)
5(x + 3)(x + 1)
4x2 + 12x + 5 = (2x + 1)(2x + 5).
Make it equal zero by subtracting 21x from both sides. 20x2 - 21x - 5 factors to (4x - 5)(5x + 1)
20x + 5 - 20 = 21x + 4 -x = 4 + 15 x = -19
4x2+20x+25 (2x+5)^2
3x - 24x + 5 + 3 = -21x + 8
To factor 4x^2 - 21x + 5, we look for two binomials in the form (Ax + B)(Cx + D) that multiply to give 4x^2 - 21x + 5. We can determine the values of A, B, C, and D by examining the factors of 4 and 5. The factored form is then (4x - 1)(x - 5).
The answer will be 21x + 1
(2x+5)(2x+5)
The factors of 5 are 1 and 5. 12 = 2 x 5 + 2 x 1, therefore: 4x2 +12x +5 = (2x + 1)(2x + 5)
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
c = 25 4x2 + 20x + 25 (2x + 5)(2x + 5)
(2x+5)(2x+1)