4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
16X + 5
12x + 5 - 2x =(12x - 2x) + 5 =10x + 5 =5 (2x + 1)
(2x+5)(2x+5)
The factors of 5 are 1 and 5. 12 = 2 x 5 + 2 x 1, therefore: 4x2 +12x +5 = (2x + 1)(2x + 5)
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
(2x+5)(2x+1)
If you mean: 4x squared+12x-40 then it is (x+5)(x-2) after dividing all terms by 4
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
Operational signs would make this a lot easier. Assuming that's + 12x + 5, the answer is (2x + 1)(2x + 5)
16X + 5
4x2+20x+25 (2x+5)^2
12x + 5 - 2x =(12x - 2x) + 5 =10x + 5 =5 (2x + 1)
(2x+5)(2x+5)
x3 - 12x2 + 35x = x (x2 - 12x + 35) = x (x - 7) (x - 5)