Yes, it is.
(x^2 - y^2) / (x - y) Apply the difference of squares formula: (x + y)(x - y) / (x - y) Assuming x is not equal to y, we can cancel terms leaving x + y When x = y, the denominator becomes 0, and the equation gives no information.
-x+y = 1 -2+y = -2 y = 1+x y = -2+2 => y = 0 By sustituting the values of x and y can be found x = -1 and y = 0 Remember that a minus from a minus is equal to a plus. So - -1+0 = 1
Suppose x and y are two POSITIVE numbers so that -x and -y are negative. Then a negative minus a negative = (-x) - (-y) = -x +y If x > y the answer is negative If x = y the answer is zero If x < y the answer is positive
2
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
it is (x-y)(x-y) :)
x = 2y y = x - 2 or x = 2y subtract 2y to both sides x - 2 = y subtract y and add 2 to both sides x - 2y = 0 multiply by -1 to both sides x - y = 2 -x + 2y = 0 x - y = 2 add these two equations together y = 2 substitute 2 for y into the first equation, x = 2y x = 2(2) = 4 Thus the solution of these linear system of equations is the point (4, 2). Check:
No, y=x-2 is linear.
(2)x=Y-4
x^2 - y^2 - 4 is in its simplest form.
33/4