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Q: What is a division problem where the quotient is larger than the dividend?

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Because it's a fraction

Quotient 0, remainder 805. Note that you will always get this pattern when you divide a smaller number by a larger one - i.e., the quotient will be zero, and the remainder will be the dividend.

A quotient is the number of times a lesser number can go into a larger number. Therefore, 24 / 3 = 8 (giving 8 as the quotient).

There are usually more zeros in dividends because it is more preferible that the larger number is in the dividends section

Because you can take a piece of an apple out of a bag of apples more times than the number of whole apples in the bag.

It's easier to visualize with smaller numbers. 18 divided by 3 = 6 18 divided by 6 = 3 If the dividend is the same, the smaller the divisor, the larger the quotient.

Rules for dividing by a fraction are multiply by the reciprocal. The reciprocal of a unit fraction is a whole number. Multiplying by a whole number will make the answer (quotient) larger. ex unit fraction 1/a 7 divided by 1/a = 7 x a/1 = 7a .... a times larger than 7.

16/4=4... 16 is the dividend

No. It is the number by which you are dividing. This may be the larger or the smaller number, depending on the problem.

The quotient is larger than the original fraction.

Multiply the two smaller numbers and see if they equal the larger number.

Then divide the remainder again by the divisor until you get a remainder smaller than your divisor or an remainder equal to zero. The remainder in a division question should never be larger than the "divisor", but the remainder often is larger than the "answer" (quotient). For example, if 435 is divided by 63, the quotient is 22 and the remainder is 57.

Division is a magnified decrease in quantity by separating one larger quantity into groups of smaller quantities. It is used to find out how many times one quantity is contained in another. It is the inverse of multiplication and is indicated by the ratio symbol (/). The result of division is known as the quotient.

You could divide the answer into the larger number of the problem. The answer should be the remaining number (multiplicand).

It gets smaller.

There are two main methods:Euclid's methodChoose one of the numbers to be the dividend of a division and the other to be the divisor.Perform the divisionIgnore the quotient and keep the remainderIf the remainder is zero, the last divisor is the GCDReplace the dividend by the divisorReplace the divisor by the last remainderRepeat from step 2.It doesn't matter which number is the dividend and which is the divisor of the first division, but if the larger is chosen as the divisor, the first run through the steps above will swap the two over so that the larger becomes the dividend and the smaller the divisor - it is better to choose the larger as the dividend in the first place. Prime factorisationExpress the numbers in their prime factorisations in power format. Multiply the common primes to their lowest power together to get the GCD.The first is limited to two numbers, but the latter can be used to find the gcd of any number of numbers.Examples:GCD of 500 and 240:Euclid's method:500 ÷ 240 = 2 r 20 240 ÷ 20 = 6 r 0gcd = 20Prime factorisation:500 = 22 x 53 240 = 24 x 3 x 5gcd = 22 x 5 = 20

The dividend is the number you are dividing so you know it is 2 divided by something. Now to get a remainder of 2, you need the divisor to be larger than than 2, so: 2/3 works as does 2/4, 2/5,2/6,2/7 and so on

The easiest way to find the greatest common denominator of two integers with a computer program is to use the Euclidean algorithm. Of the most popular methods of finding the GCD of two numbers, the Euclidean algorithm does it with the least amount of work and requires the least amount of code.In order to understand the Euclidean algorithm, you'll need to know a few division terms:The dividend is the number to be divided.The divisor is the number being divided by.The quotient is the number of times the divisor divides into the dividend.The remainder is the amount "left over" when the divisor cannot go into the dividend an integral number of times.18A divided by 12B gives a quotient of 1C and a remainder of 6D. A is the dividend, B is the divisor, C is the quotient, and D is the remainder.The Euclidean algorithm works like this:Check if either of the two integers is 0. If so, there is no solution (Ø), as a number cannot share a GCD with zero. Besides, division by zero is a big no-no.Check if either of the two integers is 1. If so, 1 is the GCD.Divide the larger of the two integers by the smaller.Divide the divisor of the previous division operation by the remainder of the previous operation.Repeat step four until the remainder equals zero. When the remainder equals zero, the divisor of the last operation is the GCD.If you still don't get it, try looking at the Euclidean algorithm in action:Find the GCD of 84 and 18.Check to see if either 84 or 18 is equal to 0. Nope. Continue on...Check to see if either 84 or 18 is equal to 1. Nope. Continue on...Since 84 is larger than 18, divide 84 by 18. Quotient is 4, remainder is 12.Take the divisor of the last operation (18) and divide it by the remainder of the last operation (12). Quotient is 1, remainder is 6.Take the divisor of the last operation (12) and divide it by the remainder of the last operation (6). Quotient is 2, remainder is 0.When the remainder is 0, the divisor of the last operation is the GCD. So the GCD in this case is 6.You should now have a good grasp of how the Euclidean algorithm works. Now we need to turn it into code. We'll need three variables, all of them integers:int divisor, dividend, remainder;The purpose of the variables is self-explanatory. Next, we need to make a few decisions. We need to decide if the dividend or the divisor is 0. If that test is passed, then we need to decide if the dividend or the divisor is 1. If that test is passed, then we need make sure that dividend is larger than divisor.if(dividend 1) {printf("The GCD is 1.\n");}// Make sure the dividend is greater than the divisor.if(divisor > dividend) {remainder = dividend;dividend = divisor;divisor = remainder;}// Calculate the GCD.while(remainder != 0) {remainder = dividend % divisor;dividend = divisor;divisor = remainder;}// Display the answer to the user.printf("The GCD is %i.\n", dividend);}And the GCD lived happily ever after. The end.

The two numerators are the same. The first denominator is smaller so the quotient is larger. As a result the first quotient is greater.

Yes, it can be , for example 9/5 gives you quotient=1 and remainder =4 and other case 16/5 gives you quotient =3 and remainder = 1

The two numerators are the same. The first denominator is smaller so the quotient is larger.

Divide the smaller into the larger. If the quotient is an integer, the smaller is a factor of the larger.

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The quotient can be smaller or larger - depending on whether the original was negative or positive. It will be unchanged if it was 0.

Only if you are dividing by a decimal or a fraction.